Part 1 — Definition

Method Overloading allows a class to have more than one method with the same name, as long as their parameter lists are different (different number of parameters or different types). This increases the readability of the program.

Part 2 — Syntax

void display(int a) { ... }
void display(String b) { ... }

Part 3 — Example

Problem: Create a "Calculator" class with an overloaded add method.

class Calculator {
    int add(int a, int b) { return a + b; }
    double add(double a, double b) { return a + b; }
}

public class Main {
    public static void main(String[] args) {
        Calculator calc = new Calculator();
        System.out.println(calc.add(5, 10));     // Calls int version
        System.out.println(calc.add(5.5, 10.5)); // Calls double version
    }
}

Part 4 — Video

Video: Coming Soon

Part 1 — Definition

Method Overriding occurs when a subclass provides a specific implementation for a method that is already defined in its superclass. The method in the subclass must have the same name, return type, and parameters as the one in the parent.

Part 2 — Syntax

class Parent {
    void show() { ... }
}
class Child extends Parent {
    @Override
    void show() { ... }
}

Part 3 — Example

Problem: Create a Shape hierarchy where each shape has its own draw method.

class Shape {
    void draw() { System.out.println("Drawing Shape"); }
}
class Circle extends Shape {
    void draw() { System.out.println("Drawing Circle"); }
}

public class Main {
    public static void main(String[] args) {
        Shape s = new Circle(); // Upcasting
        s.draw(); // Output: Drawing Circle
    }
}

Observation: Java decides which method to call at runtime based on the actual object type, not the reference type.

Part 4 — Video

Video: Coming Soon